Science Engineering Circuit Analysis & Theorems Posted by kalpit
<p>In a Norton equivalent circuit with I<sub>N</sub> = 10 A and R<sub>N</sub> = 20 ohm, and R<sub>L </sub>= 20 ohm. the current through R<sub>L</sub> is:</p>
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A) 5 A
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B) 6.66 A
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C) 10 A
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D) 3.33 A